skwdro.linear_models.LinearRegression
- class skwdro.linear_models.LinearRegression(rho=0.01, l2_reg=0.0, fit_intercept=True, cost='t-NLC-2-2', solver='entropic_torch', solver_reg=None, sampler_reg=None, n_zeta_samples: int = 10, random_state: int = 0, opt_cond: ~skwdro.solvers.optim_cond.OptCondTorch | None = <skwdro.solvers.optim_cond.OptCondTorch object>)[source]
A Wasserstein Distributionally Robust linear regression.
The cost function is

The WDRO problem solved at fitting is

- Parameters:
- rhofloat, default=1e-2
Robustness radius
- l2_regfloat, default=0.
l2 regularization
- fit_interceptboolean, default=True
Determines if an intercept is fit or not
- cost: str, default=”t-NLC-2-2”
Tiret-separated code to define the transport cost: “<engine>-<cost id>-<k-norm type>-<power>” for

- solver: str, default=’entropic’
Solver to be used: ‘entropic’, ‘entropic_torch’ (_pre or _post) or ‘dedicated’
- solver_reg: float, default=1.0
regularization value for the entropic solver
- n_zeta_samples: int, default=10
number of adversarial samples to draw
- opt_cond: Optional[OptCondTorch]
optimality condition, see
OptCondTorch
- Attributes:
- coef_array, shape (n_features,)
parameter vector (
in the cost function formula)- intercept_float
constant term in decision function.
Examples
>>> import numpy as np >>> from skwdro.linear_models import LinearRegression as RobustLinearRegression >>> from sklearn.model_selection import train_test_split >>> d = 10; m = 100 >>> x0 = np.random.randn(d) >>> X = np.random.randn(m,d) >>> y = X.dot(x0) + np.random.randn(m) >>> X_train, X_test, y_train, y_test = train_test_split(X,y) >>> rob_lin = RobustLinearRegression(rho=0.1,solver="entropic",fit_intercept=True) >>> rob_lin.fit(X_train, y_train) LinearRegression(rho=0.1) >>> y_pred_rob = rob_lin.predict(X_test)